for loop that changes specific letters to numbers

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Seaturtle
Seaturtle 2019년 10월 2일
댓글: Adam Danz 2019년 10월 4일
I want to replace the vowels AEIOU with the number 0 and all other letters with the number 1. For example the output should be ans = [0 1 1 1 0] if the user inputs apple. I know I must be misunderstanding how to get the loop to go through my whole string. This is what I have managed so far.
party = input('What is your answer? ', 's');
n = length(party)
for i = 1:n
if i == 'A'
disp(0)
elseif i == 'B'
disp(1)
elseif i == 'C'
disp(1)
end
end

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채택된 답변

Walter Roberson
Walter Roberson 2019년 10월 2일
party = input('What is your answer? ', 's');
n = length(party)
for i = 1:n
if party(i) == 'A'
party(i) = 0;
elseif i == 'B'
party(i) = 1;
elseif i == 'C'
party(i) = 1;
end
end
disp( double(party) )
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이전 댓글 5개 표시
Guillaume
Guillaume 2019년 10월 3일
It would be nice if 'vowel' were a category option.
The problem with that is what is a vowel or not depends on the language. Some letters such as 'y' in english can also qualify as a vowel or consonant depending on the word.
Adam Danz
Adam Danz 2019년 10월 3일
True. It would be neat to play around with one of the vowel classification algorithms that are not specific to any language such as this one (link below) that is based on character co-occurrences. It wouldn't necessarily solve the fuzzy set problem but it would be a semi-objective, language-independent classification.
https://www.aclweb.org/anthology/W17-4112/
https://www.aclweb.org/anthology/W17-4112.pdf

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추가 답변 (2개)

Adam Danz
Adam Danz 2019년 10월 2일
편집: Adam Danz 2019년 10월 2일
No loop needed.
str = 'apple';
isConsonant = ~ismember(lower(str),'aeiou') %lower() makes it not case sensitive
If you really wanted to do that in a loop,
n = numel(party);
isConsonant = true(1,n);
for i = 1:n
if ismember(party(i),'aeiou')
isConsonant(i) = false;
end
end
In both cases, isConsonant is a logical vector. If you want a double vector of 0/1 instead of false/true,
isConsonant = double(isConsonant);
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이전 댓글 6개 표시
Seaturtle
Seaturtle 2019년 10월 3일
편집: Seaturtle 2019년 10월 3일
Thanks for this answer! This really helped with my understanding of not using a loop to do something with shorter code.
Adam Danz
Adam Danz 2019년 10월 3일
Glad I could chip in! :)

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Jos (10584)
Jos (10584) 2019년 10월 3일
Another option:
str = 'apple';
TF1 = any(lower(str) ~= 'aeiou'.')
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Jos (10584)
Jos (10584) 2019년 10월 4일
Thanks for the corrections :-)
Adam Danz
Adam Danz 2019년 10월 4일
+1
This implicit expansion solution is faster and neater than my ismember() solution.

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