how i can find the Entropy for 3 probabilities by matlab?

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Tammun filistin
Tammun filistin 2018년 5월 27일
댓글: Ankita Bansal 2018년 6월 4일
Hello Every one
Im trying to calculate the entropy for three random values as shown in the following script , but it gives me an error . could any one please help me to find the correct answer. Many thanks.
if true
p00=[0.1 0.2 0.3 0.4 0.5 0.6 0.7 ];
p01=[0.1 0.2 0.3 0.4 0.5 0.6 0.7 ];
p02=[0.1 0.2 0.3 0.4 0.5 0.6 0.7 ];
for i=1:length(p00)
for j=1:length(p01)
for k=1:length(p02)
p03=1-p00(1,i)-p01(1,j)-p02(1,k)
H(i,j,k) = real((-p00(1,i).*log2(p00(1,i))-(p01(1,j)).*log2(p01(1,j))-p02(i,j,k).*log2((p02(i,j,k)))-p03(i,j,k).*log2((p03(i,j,k)))))
end
end
end
end

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Ankita Bansal
Ankita Bansal 2018년 5월 28일
Hi, first thing which is incorrect in your code is that you are trying to access p02(1,1,2) however p02 is 1x7 matrix. Similarly check for other syntaxes also. Second, I am not getting what are p00, p01 and p02. What is meaning of a vector here?
  댓글 수: 2
Tammun filistin
Tammun filistin 2018년 5월 28일
p00, p01 and p02 it represent a vectors of probabilities and Im looking for the corresponding entropy for all the compilations of those probabilities. Thanks
Ankita Bansal
Ankita Bansal 2018년 6월 4일
Hi
p00=[0.1 0.2 0.3 0.4 0.5 0.6 0.7 ];
p01=[0.1 0.2 0.3 0.4 0.5 0.6 0.7 ];
p02=[0.1 0.2 0.3 0.4 0.5 0.6 0.7 ];
for i=1:length(p00)
for j=1:length(p01)
for k=1:length(p02)
p03=1-p00(1,i)-p01(1,j)-p02(1,k)
H(i,j,k) = real((-p00(i).*log2(p00(i))-(p01(j)).*log2(p01(j))-p02(k).*log2((p02(k)))-p03*log2(p03)))
end
end
end
is this what you are trying to calculate?

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